What is the approximate voltage dropped in a 1-phase circuit measuring 188 ft with 8 AWG copper conductors and a current draw of 36 amperes?

To determine the approximate voltage drop in the 1-phase circuit, it is important to use the formula for voltage drop, which is commonly expressed as:

[ \text{Voltage Drop} = \frac{2 \times K \times I \times L}{1000} ]

In this formula:

• ( K ) represents the resistivity constant for the conductor material (copper in this case), which is approximately 12.9 ohms per mil foot for copper.

• ( I ) is the current in amperes (36 A).

• ( L ) is the length of the circuit run in feet (188 ft).

Since the circuit is a 1-phase circuit, the factor of 2 is used to account for the return path of the current that effectively doubles the length of the conductor.

Calculating the voltage drop step-by-step:

1. Multiply the current (36 A) by the length of the circuit (188 ft).

[

36 \times 188 = 6768

]

2. Multiply the result by 2, since the circuit is a single-phase:

[

2 \times 6768 = 13536

]

3. Now